Integrand size = 22, antiderivative size = 50 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=-i a x-\frac {i a \cot (c+d x)}{d}-\frac {a \cot ^2(c+d x)}{2 d}-\frac {a \log (\sin (c+d x))}{d} \]
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Time = 0.09 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {3610, 3612, 3556} \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=-\frac {a \cot ^2(c+d x)}{2 d}-\frac {i a \cot (c+d x)}{d}-\frac {a \log (\sin (c+d x))}{d}-i a x \]
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Rule 3556
Rule 3610
Rule 3612
Rubi steps \begin{align*} \text {integral}& = -\frac {a \cot ^2(c+d x)}{2 d}+\int \cot ^2(c+d x) (i a-a \tan (c+d x)) \, dx \\ & = -\frac {i a \cot (c+d x)}{d}-\frac {a \cot ^2(c+d x)}{2 d}+\int \cot (c+d x) (-a-i a \tan (c+d x)) \, dx \\ & = -i a x-\frac {i a \cot (c+d x)}{d}-\frac {a \cot ^2(c+d x)}{2 d}-a \int \cot (c+d x) \, dx \\ & = -i a x-\frac {i a \cot (c+d x)}{d}-\frac {a \cot ^2(c+d x)}{2 d}-\frac {a \log (\sin (c+d x))}{d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.22 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.36 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=-\frac {i a \cot (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-\tan ^2(c+d x)\right )}{d}-\frac {a \left (\cot ^2(c+d x)+2 \log (\cos (c+d x))+2 \log (\tan (c+d x))\right )}{2 d} \]
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Time = 0.38 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.00
method | result | size |
parallelrisch | \(-\frac {a \left (2 i d x +2 \ln \left (\tan \left (d x +c \right )\right )-\ln \left (\sec ^{2}\left (d x +c \right )\right )+2 i \cot \left (d x +c \right )+\cot ^{2}\left (d x +c \right )\right )}{2 d}\) | \(50\) |
derivativedivides | \(\frac {a \left (-\frac {1}{2 \tan \left (d x +c \right )^{2}}-\frac {i}{\tan \left (d x +c \right )}-\ln \left (\tan \left (d x +c \right )\right )+\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}-i \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(60\) |
default | \(\frac {a \left (-\frac {1}{2 \tan \left (d x +c \right )^{2}}-\frac {i}{\tan \left (d x +c \right )}-\ln \left (\tan \left (d x +c \right )\right )+\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}-i \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(60\) |
risch | \(\frac {2 i a c}{d}+\frac {2 a \left (2 \,{\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{2}}-\frac {a \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) | \(60\) |
norman | \(\frac {-\frac {a}{2 d}-i a x \left (\tan ^{2}\left (d x +c \right )\right )-\frac {i a \tan \left (d x +c \right )}{d}}{\tan \left (d x +c \right )^{2}}-\frac {a \ln \left (\tan \left (d x +c \right )\right )}{d}+\frac {a \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d}\) | \(74\) |
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Time = 0.24 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.66 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=\frac {4 \, a e^{\left (2 i \, d x + 2 i \, c\right )} - {\left (a e^{\left (4 i \, d x + 4 i \, c\right )} - 2 \, a e^{\left (2 i \, d x + 2 i \, c\right )} + a\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right ) - 2 \, a}{d e^{\left (4 i \, d x + 4 i \, c\right )} - 2 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d} \]
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Time = 0.15 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.60 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=- \frac {a \log {\left (e^{2 i d x} - e^{- 2 i c} \right )}}{d} + \frac {4 a e^{2 i c} e^{2 i d x} - 2 a}{d e^{4 i c} e^{4 i d x} - 2 d e^{2 i c} e^{2 i d x} + d} \]
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Time = 0.30 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.16 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=-\frac {2 i \, {\left (d x + c\right )} a - a \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 2 \, a \log \left (\tan \left (d x + c\right )\right ) + \frac {2 i \, a \tan \left (d x + c\right ) + a}{\tan \left (d x + c\right )^{2}}}{2 \, d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 102 vs. \(2 (44) = 88\).
Time = 0.45 (sec) , antiderivative size = 102, normalized size of antiderivative = 2.04 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=-\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 16 \, a \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + i\right ) + 8 \, a \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) - 4 i \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - \frac {12 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4 i \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - a}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}}}{8 \, d} \]
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Time = 4.93 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.94 \[ \int \cot ^3(c+d x) (a+i a \tan (c+d x)) \, dx=-\frac {a\,\mathrm {atan}\left (2\,\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,2{}\mathrm {i}}{d}-\frac {\frac {a}{2}+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}}{d\,{\mathrm {tan}\left (c+d\,x\right )}^2} \]
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